Current Electricity Charging Discharging Of Capacitors Question 262
Question: In the given figure, battery E is balanced on 55 cm length of potentiometer wire but when a resistance of 10 W is connected in parallel with the battery then it balances on 50 cm length of the potentiometer wire then internal resistance r of the battery is
[DCE 2000; RPET 2000]
Options:
A) 1 W
B) 3 W
C) 10 W
D) 5 W
Show Answer
Answer:
Correct Answer: A
Solution:
$ r=( \frac{l _{1}-l _{2}}{l _{2}} )\times R’ $
$ \Rightarrow r=( \frac{55-50}{50} )\times 10=1\Omega $ .
BETA
