Dual Nature Of Light Question 131
Question: For the Bohr’s first orbit of circumference $ 2\pi r $ , the de-Broglie wavelength of revolving electron will be [MP PMT 1987]
Options:
A) $ 2\pi r $
B) $ \pi r $
C) $ \frac{1}{2\pi r} $
D) $ \frac{1}{4\pi r} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ mvr=\frac{nh}{2\pi } $ According to Bohr?s theory
Þ $ 2\pi r=n,( \frac{h}{mv} )=n\lambda $ for $ n=1 $ , $ \lambda =2\pi r $
BETA
