Dual Nature Of Light Question 142
According to de-Broglie, the de-Broglie wavelength for electron in an orbit of hydrogen atom is 10⁻⁹ m. The principle quantum number for this electron is [RPMT 2003]
Options:
1
2
3
4
Show Answer
Answer:
Correct Answer: C
Solution:
$ 2\pi ,r,n=\lambda \Rightarrow n=\frac{\lambda }{2\pi ,r}=\frac{{{10}^{-9}}}{2\times 3.14\times 5.13\times {{10}^{-11}}}=285 $
BETA
