Dual Nature Of Light Question 144
Question: The kinetic energy of electron and proton is $ {{10}^{-32}}J $ . Then the relation between their de-Broglie wavelengths is [CPMT 1999]
Options:
A) $ {\lambda_{p}}<{\lambda_{e}} $
B) $ {\lambda_{p}}>{\lambda_{e}} $
C) $ {\lambda_{p}}={\lambda_{e}} $
D) $ {\lambda_{p}}=2{\lambda_{e}} $
Show Answer
Answer:
Correct Answer: A
Solution:
By using $ \lambda =\frac{h}{\sqrt{2mE}} $ E = 10?32 J = Constant for both particles. Hence $ \lambda \propto \frac{1}{\sqrt{m}} $ Since $ m_{p}>m_{e} $ so $ {\lambda_{p}}<{\lambda_{e}}. $
BETA
