Dual Nature Of Light Question 145
Question: The de-Broglie wavelength of a particle accelerated with 150 volt potential is $ {{10}^{-10}} $ m. If it is accelerated by 600 volts p.d., its wavelength will be [RPET 1988]
Options:
A) 0.25 Å
B) 0.5 Å
C) 1.5 Å
D) 2 Å
Show Answer
Answer:
Correct Answer: B
Solution:
By using $ \lambda ,\propto \frac{1}{\sqrt{V}} $
Þ $ \frac{{\lambda_{1}}}{{\lambda_{2}}}=\sqrt{\frac{V_{2}}{V_{1}}} $
Þ $ \frac{{{10}^{-10}}}{{\lambda_{2}}}=\sqrt{\frac{600}{150}}=2 $
Þ l2 = 0.5 Å.
BETA
