Dual Nature Of Light Question 148
Question: The de-Broglie wavelength of a neutron at 27oC is l. What will be its wavelength at 927oC [DPMT 2002]
Options:
A) l / 2
B) l / 3
C) l / 4
D) l / 9
Show Answer
Answer:
Correct Answer: A
Solution:
$ {\lambda_{neutron}}\propto \frac{1}{\sqrt{T}} $
Þ $ \frac{{\lambda_{1}}}{{\lambda_{2}}}=\sqrt{\frac{T_{2}}{T_{1}}} $
Þ $ \frac{\lambda }{{\lambda_{2}}}=\sqrt{\frac{(273+927)}{(273+27)}}=\sqrt{\frac{1200}{300}}=2 $
Þ $ {\lambda_{2}}=\frac{\lambda }{2}. $
BETA
