Dual Nature Of Light Question 155
Question: The kinetic energy of an electron is 5 eV. Calculate the de-Broglie wavelength associated with it (h = 6.6 ´ 10?34 Js, me = 9.1 ´ 10?31 kg) [Pb. PMT 2004]
Options:
A) 5.47 Å
B) 10.9 Å
C) 2.7 Å
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ \lambda =\frac{h}{\sqrt{2mE}}=\frac{6.6\times {{10}^{-34}}}{\sqrt{2\times 9.1\times {{10}^{-31}}\times 5\times 1.6\times {{10}^{-19}}}} $ $ =5.469\times {{10}^{-10}}m=5.47{\AA} $
BETA
