Dual Nature Of Light Question 182
The magnetic field associated with a light wave is given at the origin by $ B=B_{0}[sin(3.14\times 10^{7}t)+sin(6.28\times {{10}^{-7}}t)]. $ If this light falls on a silver plate having a work function of 4.7 eV, what will be the maximum kinetic energy (in eV) of the photoelectrons? $ (c=3\times 10^{8}m{{s}^{-1}},h=6.6\times {{10}^{-34}}J-s) $
Solution:
Answer: 7.7
BETA
