Dual Nature Of Light Question 185
Question: If the de Broglie wavelength of an electron is equal to $ ~{{10}^{-3}} $ times the wavelength of a photon of frequency $ 6\times 10^{14} $ then the speed (in m/s) of electron is equal to: (Speed of light $ =3\times 10^{8}m/s $ ) Planck’s constant $ =6.63\times {{10}^{-34}}J.s $ Mass of electron $ =9.1\times {{10}^{-31}}kg $ )
Solution:
Answer: $ ( 1.45\times 10^{6} ) $
BETA
