Dual Nature Of Light Question 190
The electric field of light wave is given as $ \overrightarrow{E}=10^{3}\cos \left( \frac{2\pi x}{5\times {{10}^{-7}}}-2\pi \times 6\times 10^{14}t \right)\hat{x}\frac{N}{C} $ This light falls on a metal plate of work function 2eV. The stopping potential (in V) of the photo-electrons is: Given, $ E,(ineV)=\frac{12375}{\lambda ,(in,\overset{o}{\mathop{A}},)} $
Solution:
Answer: 0.48
BETA
