Dual Nature Of Light Question 217
Question: An AIR station is broadcasting the waves of wavelength 300 metres. If the radiating power of the transmitter is 10 kW, then the number of photons radiated per second is [MP PET 1989; RPMT 2000]
Options:
A) $ 1.5\times 10^{29} $
B) $ 1.5\times 10^{31} $
C) $ 1.5\times 10^{33} $
D) $ 1.5\times 10^{35} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ P=\frac{W}{t}=\frac{nhc}{\lambda t},\Rightarrow ( \frac{n}{t} )=\frac{P\lambda }{hc} $ $ =\frac{10\times 10^{3}\times 300}{6.6\times {{10}^{-34}}\times 3\times 10^{8}} $ $ =1.5\times 10^{31} $
BETA
