Dual Nature Of Light Question 218
Question: The energy of a photon is $ E=hv $ and the momentum of photon $ p=\frac{h}{\lambda } $ , then the velocity of photon will be [CPMT 1991]
Options:
E/p
Ep
C) $ {{( \frac{E}{p} )}^{2}} $
D) $ 3\times 10^{8}m/s $
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Answer:
Correct Answer: A
Solution:
Momentum of photon $ p=\frac{E}{c} $
$ \Rightarrow $ Velocity of photon $ c=\frac{E}{p} $
BETA
