Dual Nature Of Light Question 224
Question: Momentum of a photon of wavelength l is [CBSE PMT 1993; JIPMER 2001, 02]
Options:
A) $ \frac{h}{\lambda } $
B) Zero
C) $ \frac{h\lambda }{c^{2}} $
D) $ \frac{h\lambda }{c} $
Show Answer
Answer:
Correct Answer: A
Solution:
Since $ h\nu =mc^{2} $ , hence $ p=mc=\frac{h\nu }{c}=\frac{h}{\lambda } $
BETA
