A) $ \frac{h}{\lambda } $
B) Zero
C) $ \frac{h\lambda }{c^{2}} $
D) $ \frac{h\lambda }{c} $
Correct Answer: A
Since $ h\nu =mc^{2} $ , hence $ p=mc=\frac{h\nu }{c}=\frac{h}{\lambda } $
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