Dual Nature Of Light Question 234
Question: Energy of photon whose frequency is $ 10^{12}MHz, $ will be [MH CET 2002]
Options:
A) $ 4.14\times 10^{3}keV $
B) $ 4.14\times 10^{2}eV $
C) $ 4.14\times 10^{3}MeV $
D) $ 4.14\times 10^{3}eV $
Show Answer
Answer:
Correct Answer: D
Solution:
$ E(eV)=\frac{h\nu }{e}=\frac{6.0\times {{10}^{-34}}\times 10^{12}\times 10^{6}}{1.6\times {{10}^{-19}}} $ $ =4.14\times 10^{3}eV $ .
BETA
