Dual Nature Of Light Question 256
Question: A radio transmitter operates at a frequency of 880 kHz and a power of 10 kW. The number of photons emitted per second are [CBSE PMT 1990; MP PET 1990]
Options:
A) $ 1.72\times 10^{31} $
B) $ 1327\times 10^{34} $
C) $ 13.27\times 10^{34} $
D) $ 0.075\times {{10}^{-34}} $
Show Answer
Answer:
Correct Answer: A
Solution:
Number of photons emitted per second $ n=\frac{p}{h\nu }=\frac{10\times 10^{3}}{6.6\times {{10}^{-34}}\times 880\times 10^{3}}=1.72\times 10^{31} $
BETA
