Dual Nature Of Light Question 265

Question: Assuming photoemission to take place, the factor by which the maximum velocity of the emitted photoelectrons changes when the wavelength of the incident radiation is increased four times, is [Haryana CEE 1996]

Options:

A) 4

B) $ \frac{1}{4} $

C) 2

D) $ \frac{1}{2} $

Show Answer

Answer:

Correct Answer: D

Solution:

$ \frac{hc}{\lambda }=W_{0}+\frac{1}{2}mv_{\max }^{2} $ Assuming $ W_{0} $ to be negligible in comparison to $ \frac{hv}{\lambda } $ i.e. $ v_{\max }^{2}\propto \frac{1}{\lambda }\Rightarrow {v_{\max }}\propto \frac{1}{\sqrt{\lambda }} $ . (On increasing wavelength l to 4l, vmax becomes half).



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