Dual Nature Of Light Question 269
Question: If the work function of a metal is $ ‘\varphi ’ $ and the frequency of the incident light is $ ‘\nu ’ $ , there is no emission of photoelectron if
Options:
A) $ \nu <\frac{\varphi }{h} $
B) $ \nu =\frac{\varphi }{h} $
C) $ \nu >\frac{\varphi }{h} $
D) $ \nu >\ =\ <\frac{\varphi }{h} $
Show Answer
Answer:
Correct Answer: A
Solution:
For no emission of photoelectron, energy of incident light < Work function
$ \Rightarrow h\nu <\varphi ,\Rightarrow ,\nu <\frac{\varphi }{h} $
BETA
