Dual Nature Of Light Question 275
Question: Light of wavelength 5000 Å falls on a sensitive plate with photoelectric work function of 1.9 eV. The kinetic energy of the photoelectron emitted will be [CBSE PMT 1998]
Options:
A) 0.58 eV
B) 2.48 eV
C) 1.24 eV
D) 1.16 eV
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Answer:
Correct Answer: A
Solution:
$ E=W_{0}+{K_{\max }};E=\frac{12375}{5000}=2.475,eV $
$ \therefore ,{K_{\max }}=E-W_{0}=2.475-1.9=0.57,eV $