Dual Nature Of Light Question 280
Question: The frequency of the incident light falling on a photosensitive metal plate is doubled, the kinetic energy of the emitted photoelectrons is [Roorkee 1992]
Options:
A) Double the earlier value
B) Unchanged
C) More than doubled
D) Less than doubled
Show Answer
Answer:
Correct Answer: C
Solution:
$ E=W_{0}+{K_{\max }}\Rightarrow {K_{\max }}=E-W_{0}=h\nu -W_{0} $
$ \Rightarrow K_{1}=h\nu -W_{0} $ and $ K_{2}=2h\nu -W_{0} $
$ \Rightarrow K_{2}>2K_{1} $
BETA
