Dual Nature Of Light Question 286
Question: What is the stopping potential when the metal with work function 0.6 eV is illuminated with the light of 2 eV [BHU 1998; MH CET 2003]
Options:
A) 2.6 V
B) 3.6 V
C) 0.8 V
D) 1.4 V
Show Answer
Answer:
Correct Answer: D
Solution:
$ V_{0}=\frac{(E-W_{0})}{e}=\frac{(2eV-0.6,eV)}{e}=1.4V $
BETA
