Dual Nature Of Light Question 291
Question: For intensity I of a light of wavelength 5000Å the photoelectron saturation current is 0.40 $ \mu ,A $ and stopping potential is 1.36 V, the work function of metal is [RPET 1999]
Options:
A) 2.47 eV
B) 1.36 eV
C) 1.10 eV
D) 0.43 eV
Show Answer
Answer:
Correct Answer: C
Solution:
By using $ E=W_{0}+{K_{\max }} $ $ E=\frac{12375}{5000}=2.475\ eV $ and $ {K_{\max }}=eV_{0}=1.36\ eV $ So $ 2.475=W_{0}+1.36\Rightarrow W_{0}=1.1\ eV $ .
BETA
