Dual Nature Of Light Question 305
Question: The photoelectric threshold wavelength for potassium (work function being $ 2eV $ ) is [CPMT 2001]
Options:
A) 310 nm
B) 620 nm
C) 1200 nm
D) 2100 nm
Show Answer
Answer:
Correct Answer: B
Solution:
$ \lambda =\frac{12375}{W_{0}}=\frac{12375}{2}=6187.5{\AA} $ $ =620\ nm $
BETA
