Dual Nature Of Light Question 308
Question: The lowest frequency of light that will cause the emission of photoelectrons from the surface of a metal (for which work function is 1.65 eV) will be [JIPMER 2002]
Options:
A) $ 4\times 10^{10}Hz $
B) $ 4\times 10^{11}Hz $
C) $ 4\times 10^{14}Hz $
D) $ 4\times {{10}^{-10}}Hz $
Show Answer
Answer:
Correct Answer: C
Solution:
Minimum frequency : $ W_{0}=h{\nu_{0}} $
Þ $ {\nu_{0}}=\frac{W_{0}}{h}=\frac{1.65\times 1.6\times {{10}^{-19}}}{6.6\times {{10}^{-34}}}=4\times 10^{14}Hz $
BETA
