Dual Nature Of Light Question 314
Question: The number of photons of wavelength 540 nm emitted per second by an electric bulb of power 100W is (taking h = $ 6\times {{10}^{-34}},J\text{-}sec $ ) [Kerala (Engg.) 2002; Pb. PET 2001]
Options:
A) 100
B) 1000
C) $ 3\times 10^{20} $
D) $ 3\times 10^{18} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ p=\frac{nhc}{\lambda t}\Rightarrow 100=\frac{n\times 6\times {{10}^{-34}}\times 3\times 10^{8}}{540\times {{10}^{-9}}\times 1} $ Þ $ n=3\times 10^{20} $
BETA
