Dual Nature Of Light Question 327
Question: A photon of energy 8 eV is incident on a metal surface of threshold frequency $ 1.6\times 10^{15},Hz $ , then the maximum kinetic energy of photoelectrons emitted is $ (h=6.6\times {{10}^{-34}},Js) $ [Pb. PET 2002]
Options:
A) 4.8 eV
B) 2.4 eV
C) 1.4 eV
D) 0.8 eV
Show Answer
Answer:
Correct Answer: C
Solution:
Work function $ W_{0}=h{\nu_{0}}=6.6\times {{10}^{-34}}\times 1.6\times 10^{15} $ $ =1.056\times {{10}^{-18}}J $ $ =6.6,eV $ From $ E=W_{0}+{K_{\max }},\Rightarrow {K_{\max }}=E-W_{0} $ $ =1.4,eV $
BETA
