Dual Nature Of Light Question 329
Question: The ratio of the energy of a photon with $ \lambda =150,nm $ to that with $ \lambda =300,nm $ is [DCE 2003]
Options:
A) 2
B) 1/4
C) 4
D) 1/2
Show Answer
Answer:
Correct Answer: A
Solution:
$ E=\frac{hc}{\lambda }\Rightarrow \frac{E_{1}}{E_{2}}=\frac{300}{150}=\frac{2}{1} $
BETA
