Dual Nature Of Light Question 346
Question: A particle of mass M at rest decays into two particles of masses $ m_{1} $ and $ m_{2} $ having non-zero velocities. The ratio of the de Broglie wavelengths of the particles, $ {\lambda_{1}}/{\lambda_{2}}, $ is
Options:
A) $ m_{1}/m_{2} $
B) $ m_{2}/m_{1} $
C) 1.0
D) $ \sqrt{m_{2}}/\sqrt{m_{1}} $
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Answer:
Correct Answer: C
Solution:
[c] Applying conservation of linear momentum, Initial momentum = Final momentum $ 0=m_{1}v_{1}-m_{2}v_{2}\Rightarrow m_{1}v_{1}=m_{2}v_{2} $ Now, $ \frac{{\lambda_{1}}}{{\lambda_{2}}}=\frac{h/m_{1}v_{1}}{h/m_{2}v_{2}}=1 $
BETA
