Dual Nature Of Light Question 362
Question: An $ \alpha $ -particle having a de-Broglie wavelength $ {\lambda_{i}} $ collides with a stationary carbon nucleus. The $ \alpha $ -particle moves off in a different direction as shown below. After the collision, the de Broglie wavelengths of the $ \alpha $ -particle and the carbon nucleus are $ {\lambda_{f}} $ and $ {\lambda_{e}} $ respectively. Which of the following relations about de Broglie wavelengths is correct
Options:
A) $ {\lambda_{i}}<{\lambda_{f}} $
B) $ {\lambda_{i}}>{\lambda_{f}} $
C) $ {\lambda_{f}}={\lambda_{i}} $
D) $ {\lambda_{i}}={\lambda_{e}} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Final speed of $ \alpha $ -particle will be less than the initial speed therefore, $ ( \frac{h}{{\lambda_{f}}} )<( \frac{h}{{\lambda_{i}}} )\text{ or }{\lambda_{f}}>{\lambda_{i}} $
BETA
