Dual Nature Of Light Question 371
Question: The maximum kinetic energy of the electrons hitting a target so as to produce X-ray of wavelength 1 A is
Options:
A) 1.24keV
B) 12.4keV
C) 124keV
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ {\lambda_{\min }}=1\overset{o}{\mathop{A}}, $ (given)
$ \therefore {\lambda_{\min }}=\frac{1240}{E}(eV)(nm) $ $ \text{Thus, }E=\frac{1240(eV)(nm)}{0.01(nm)}=12400eV $ $ E=12.4KeV $
BETA
