Dual Nature Of Light Question 378
Question: When the minimum wavelength of X-rays is 2A then the applied potential difference between cathode and anticathode will be
Options:
A) 6.2kV
B) 2.48 kV
C) 24.8kV
D) 62kV
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ V=\frac{12400}{{\lambda_{\min }}( \overset{o}{\mathop{A}}, )}Volt\Rightarrow V=\frac{12400}{2}=6.2KV $
BETA
