Dual Nature Of Light Question 380
Question: The short wavelength limit of continuous X-radiation emitted by an X-ray tube operating at 30 kV is 0.414 A. Calculate Planck’s constant.
Options:
A) $ 6\text{.22 }\times\text{ 1}{{0}^{\text{-34}}}\text{erg-sec} $
B) $ 6\text{.624 }\times\text{ 1}{{0}^{\text{-24}}}\text{erg-sec} $
C) $ 6\text{.624 }\times\text{ 1}{{0}^{\text{-27}}}\text{J-sec} $
D) $ 6\text{.624 }\times\text{ 1}{{0}^{\text{-34}}}\text{J-sec} $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ {\lambda_{\min }}=\frac{ch}{eV}\therefore h=( \frac{eV}{c} ){\lambda_{\min }} $ $ h=\frac{1.6\times {{10}^{-19}}\times 30000\times 0.141\times {{10}^{-10}}}{3\times 10^{8}} $
$ \Rightarrow h=6.624\times {{10}^{-34}}J-\sec $
BETA
