Dual Nature Of Light Question 382
Question: An X-ray tube is operated at 15 kV. Calculate the upper limit of the speed of the electrons striking the target.
Options:
A) $ 7.26\times 10^{7}m/s $
B) $ 7.62\times 10^{7}m/s $
C) $ 7.62\times 10^{7}cm/s $
D) $ 7.26\times 10^{9}m/s. $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] The maximum kinetic energy of an electron accelerated through a potential difference of V volt is $ \frac{1}{2}mv^{2}=eV $
$ \therefore $ Maximum velocity $ v=\sqrt{\frac{2eV}{m}} $ $ v=\sqrt{\frac{2\times 1.6\times {{10}^{-19}}\times 15000}{9.1\times {{10}^{-31}}}}, $ $ v=7.26\times 10^{7}m/s $
BETA
