Dual Nature Of Light Question 404
Question: Electromagnetic radiation falls on a metallic body whose work function is 2eV. For a particular radiation of frequency v, the maximum kinetic energy of the photoelectron is found to be 4 eV. What would be the maximum kinetic energy of 5v photoelectron for the radiation of frequency $ \frac{5v}{3} $ ?
Options:
A) $ \frac{8}{3}eV $
B) $ 8eV $
C) $ \frac{10}{3}eV $
D) $ \frac{20}{3}eV $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ hv=\phi +{K_{\max }} $ $ hv=2+4=6eV $ $ \text{Now, }h( \frac{5}{3}v )\text{ =2+}{{K}{\max }} $ $ {K{\max }}=\frac{5}{3}\times 6-2\Rightarrow {K_{\max }}=8eV. $
BETA
