Dual Nature Of Light Question 419
Question: The kinetic energy of electron and proton is $ {{10}^{-32}}J $ . Then the relation between their de-Broglie wavelengths is
Options:
A) $ {\lambda_{p}}<{\lambda_{e}} $
B) $ {\lambda_{p}}>{\lambda_{e}} $
C) $ {\lambda_{p}}={\lambda_{e}} $
D) $ {\lambda_{p}}=2{\lambda_{e}} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] By using $ \lambda =\frac{h}{\sqrt{2mE}} $
$ E={{10}^{-32}}J=Constante $ for both particles.
Hence $ \lambda \propto \frac{1}{\sqrt{m}} $
Since $ m_{p}>m_{e} $ so $ {\lambda_{p}}<{\lambda_{e}}. $
BETA
