Dual Nature Of Light Question 423
Question: The approximate wavelength of a photon of energy 2.48 eV is
Options:
A) 500 $ \overset{o}{\mathop{A}}, $
B) 5000 $ \overset{o}{\mathop{A}}, $
C) 2000 $ \overset{o}{\mathop{A}}, $
D) 1000 $ \overset{o}{\mathop{A}}, $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] By using $ E(eV)=\frac{12375}{\lambda (\overset{o}{\mathop{A}},)} $
$ \Rightarrow \lambda ,=\frac{12375}{2.48}=4989.9,\overset{o}{\mathop{A}}\approx ,5000,\overset{o}{\mathop{A}}, $
BETA
