Dual Nature Of Light Question 433
Question: 4 eV is the energy of the incident photon and the work function in $ 2eV. $ What is the stopping potential
Options:
A) 2V
B) 4V
C) 6V
D) $ 2\sqrt{2}V $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ E=W_{0}+eV_{0}\Rightarrow 4eV=2eV+eV_{0}\Rightarrow V_{0}=2\ volt $
BETA
