Dual Nature Of Light Question 433

Question: 4 eV is the energy of the incident photon and the work function in $ 2eV. $ What is the stopping potential

Options:

A) 2V

B) 4V

C) 6V

D) $ 2\sqrt{2}V $

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ E=W_{0}+eV_{0}\Rightarrow 4eV=2eV+eV_{0}\Rightarrow V_{0}=2\ volt $



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