Dual Nature Of Light Question 434
Question: The number of photons of wavelength 540 nm emitted per second by an electric bulb of power 100W is (taking h = $ 6\times {{10}^{-34}},J\text{-}sec $ )
Options:
A) 100
B) 1000
C) $ 3\times 10^{20} $
D) $ 3\times 10^{18} $
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Answer:
Correct Answer: C
Solution:
[c] $ p=\frac{nhc}{\lambda t}\Rightarrow 100=\frac{n\times 6\times {{10}^{-34}}\times 3\times 10^{8}}{540\times {{10}^{-9}}\times 1} $
$ \Rightarrow $ $ n=3\times 10^{20} $
BETA
