Dual Nature Of Light Question 439
Question: An electron of mass m when accelerated through a potential difference V has de-Broglie wavelength $ \lambda $ . The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be
Options:
A) $ \lambda \frac{m}{M} $
B) $ \lambda \sqrt{\frac{m}{M}} $
C) $ \lambda \frac{M}{m} $
D) $ \lambda \sqrt{\frac{M}{m}} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ \lambda =\frac{h}{\sqrt{2mE}} $
$ \Rightarrow $ $ \lambda \propto \frac{1}{\sqrt{m}} $ (E = same)
BETA
