Dual Nature Of Light Question 455
Question: Light of frequency $ 8\times 10^{15}Hz $ is incident on a substance of photoelectric work function $ 6.125,eV. $ The maximum kinetic energy of the emitted photoelectrons is
Options:
A) 17 $ eV $
B) 22 $ eV $
C) 27 $ eV $
D) 37 $ eV $
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Answer:
Correct Answer: C
Solution:
[c] $ E=h\nu =6.6\times {{10}^{-34}}\times 8\times 10^{15}=5.28\times {{10}^{-18}}J=33eV $ By using $ E=W_{0}+{K_{\max }}\Rightarrow {K_{\max }}=E-W_{0} $ $ =33-6.125=27eV $
BETA
