Dual Nature Of Light Question 465
If the cathode-to-anode potential difference in an X-ray tube is 105 V, then the maximum energy of X-ray photon can be
Options:
A) 105 J
B) 105 MeV
C) 10?1 MeV
D) 105 KeV
Show Answer
Answer:
Correct Answer: C
Solution:
Since $ {\lambda_{\min }}=\frac{12375}{V}{\AA} $ $ =\frac{12375}{10^{5}},{\AA}=0.123,{\AA} $ $ {E_{\max }}=\frac{hc}{{\lambda_{\min }}}; $ On putting the values. $ {E_{\max }}\cong {{10}^{-1}}MeV. $
BETA
