Dual Nature Of Light Question 478

Question: If V be the accelerating voltage, then the maximum frequency of continuous X-rays is given by [NCERT 1971; CPMT 1991; MP PET 2000; RPMT 2001; MP PMT 2002]

Options:

A) $ \frac{eh}{V} $

B) $ \frac{hV}{e} $

C) $ \frac{eV}{h} $

D) $ \frac{h}{eV} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ E=eV=h{\nu_{\max }},\Rightarrow ,{\nu_{\max }}=\frac{eV}{h} $