Dual Nature Of Light Question 478
Question: If V be the accelerating voltage, then the maximum frequency of continuous X-rays is given by [NCERT 1971; CPMT 1991; MP PET 2000; RPMT 2001; MP PMT 2002]
Options:
A) $ \frac{eh}{V} $
B) $ \frac{hV}{e} $
C) $ \frac{eV}{h} $
D) $ \frac{h}{eV} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ E=eV=h{\nu_{\max }},\Rightarrow ,{\nu_{\max }}=\frac{eV}{h} $