Dual Nature Of Light Question 481
Question: A potential difference of 42,000 volts is used in an X-ray tube to accelerate electrons. The maximum frequency of the X?radiations produced is [MP PMT 1993]
Options:
A) $ 10^{19}Hz $
B) $ 10^{18},Hz $
C) $ 10^{16}Hz $
D) $ 10^{20}Hz $ $ (1,eV=1.6\times {{10}^{-19}}J $ and $ h=6.63\times {{10}^{-34}}J-\sec ) $
Show Answer
Answer:
Correct Answer: A
Solution:
$ h{\nu_{o}}=eV $
$ \therefore ,{\nu_{o}}=\frac{eV}{h}=\frac{1.6\times {{10}^{-19}}\times 42000}{6.63\times {{10}^{-34}}}=10^{19},Hz $
BETA
