Dual Nature Of Light Question 51
Question: The radius of the orbital of electron in the hydrogen atom 0.5 Å. The speed of the electron is $ 2\times 10^{6}m/s $ . Then the current in the loop due to the motion of the electron is [RPMT 1996]
Options:
A) 1 mA
B) 1.5 mA
C) 2.5 mA
D) $ 1.5\times {{10}^{-2}}mA $
Show Answer
Answer:
Correct Answer: A
Solution:
Time period of revolution of electron $ T=\frac{2\pi }{\omega }=\frac{2\pi r}{v} $ Hence corresponding electric current $ i=\frac{e}{T}=\frac{ev}{2\pi r} $
$ \Rightarrow i=\frac{1.6\times {{10}^{-19}}\times 2\times 10^{6}}{2\times 3.14\times 0.5\times {{10}^{-10}}}=1,mA. $
BETA
