Dual Nature Of Light Question 530
Question: An X-ray tube with a copper target emits Cu $ {K_{\alpha }} $ line of wavelength 1.50 Å. What should be the minimum voltage through which electrons are to be accelerated to produce this wavelength of X rays $ (h=6.63\times {{10}^{-34}}J\text{-}\sec ,\ c=3\times 10^{8}m/s) $ [Orissa JEE 1996]
Options:
A) 8280 V
B) 828 V
C) 82800 V
D) 8.28 V
Show Answer
Answer:
Correct Answer: A
Solution:
$ eV=\frac{hc}{\lambda }=\frac{6.63\times {{10}^{-34}}\times 3\times 10^{8}}{1.5\times {{10}^{-10}}} $
$ \Rightarrow V=\frac{6.63\times {{10}^{-34}}\times 3\times 10^{8}}{1.6\times {{10}^{-19}}\times 1.5\times {{10}^{-10}}} $ =8280 Volt.
BETA
