Dual Nature Of Light Question 77
Question: An $\alpha$ particle is accelerated through a p.d of $ 10^{6} $ volt then K.E. of particle will be [Pb. PET 2003]
Options:
A) 8 MeV
B) 4 MeV
C) 2 MeV
D) 1 MeV
Show Answer
Answer:
Correct Answer: C
Solution:
$ K=Q.\Delta V=(2e)\times 10^{6}V=2\times 10^{6}eV=2M,eV $
BETA
