Dual Nature Of Light Question 84
Question: In Millikan?s oil drop experiment, an oil drop of mass $ 16\times {{10}^{-6}}kg $ is balanced by an electric field of $ 10^{6}V/m. $ The charge in coulomb on the drop, assuming $ g=10,m/s^{2} $ is [UP SEAT 2005]
Options:
A) $ 6.2\times {{10}^{-11}} $
B) $ 16\times {{10}^{-9}} $
C) $ 16\times {{10}^{-11}} $
D) $ 16\times {{10}^{-13}} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ eE=mg $ Þ $ e=\frac{mg}{E} $ $ =\frac{16\times {{10}^{-6}}\times 10}{10^{6}}=16\times {{10}^{-11}} $ C.
BETA
