Electro Magnetic Induction And Alternating Currents Question 322
Question: A conducting rod of length 2l is rotating with constant angular speed w about its perpendicular bisector. A uniform magnetic field $ \overrightarrow{B} $ exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is [MP PET 2001]
Options:
A) Bwl2
B) $ \frac{1}{2}B\omega l^{2} $
C) $ \frac{1}{8}B\omega l^{2} $
D) Zero
Show Answer
Answer:
Correct Answer: D
Solution:
Potential difference between O and A is $ V_{0}-V_{A}=\frac{1}{2}Bl^{2}\omega $ O and B is $ V_{0}-V_{B}=\frac{1}{2}Bl^{2}\omega $ so $ V_{A}-V_{B}=0 $
BETA
