Electro Magnetic Induction And Alternating Currents Question 33
Question: The reactance of a $ 25,\mu F $ capacitor at the ac frequency of 4000 Hz is
Options:
A) $ \frac{5}{\pi } $ ohm
B) $ \sqrt{\frac{5}{\pi }} $ ohm
C) 10 ohm
D) $ \sqrt{10} $ ohm
Show Answer
Answer:
Correct Answer: A
Solution:
$ X_{C}=\frac{1}{2\pi \nu C}=\frac{1}{2\pi \times 4000\times 25\times {{10}^{-6}}}=\frac{5}{\pi }\Omega $
BETA
