Electro Magnetic Induction And Alternating Currents Question 387
Question: A coil has an area of 0.05 m2 and it has 800 turns. It is placed perpendicularly in a magnetic field of strength $ 4\times {{10}^{-5}},Wb/m^{2}, $ it is rotated through $ 90^{o} $ in 0.1 sec. The average e.m.f. induced in the coil is [CPMT 2001]
Options:
A) 0.056 V
B) 0.046 V
C) 0.026 V
D) 0.016 V
Show Answer
Answer:
Correct Answer: D
Solution:
$ e=-\frac{NBA(\cos {\theta_{2}}-\cos {\theta_{1}})}{\Delta t} $ $ =-\frac{800\times 4\times {{10}^{-5}}\times 0.05,(\cos 90^{o}-\cos 0^{o})}{0.1} $ = 0.016 V
BETA
