Electro Magnetic Induction And Alternating Currents Question 208
Question: The primary and secondary coil of a transformer have 50 and 1500 turns respectively. If the magnetic flux $ \phi $ linked with the primary coil is given by $ \phi ={\phi_{0}}+4t $ , where $ \phi $ is in webers, t is time in seconds and $ {\phi_{0}} $ is a constant, the output voltage across the secondary con is
Options:
A) 120 volts
B) 220 volts
C) 30 volts
D) 90 volts
Show Answer
Answer:
Correct Answer: A
Solution:
-
Since $ \frac{V_{s}}{V_{p}}=\frac{N_{s}}{N_{p}} $
Where $ N_{s} $ = No. of turns across primary coil = 50
$ N_{p} $ = No. of turns across secondary coil = 1500 and
$ V_{p}=\frac{d\phi }{dt}=\frac{d}{dt}({\phi_{0}}+4t)=4\Rightarrow V=\frac{1500}{50}\times 4 $ =120 V
BETA
